WebJun 27, 2016 · Explanation: Multiplying both sides by 2 in given equality cosAcosB + sinAsinBsinC = 1, we get 2cosAcosB +2sinAsinBsinC = 2 or 2cosAcosB +2sinAsinBsinC = (sin2A +cos2A) + (sin2B + cos2B) or (cos2A+ cos2B − 2cosAcosB) +(sin2A+ sin2B −2sinAsinB) + 2sinAsinB − 2sinAsinBsinC = 0 or or (cosA− cosB)2 + (sinA −sinB)2 + … WebDec 24, 2024 · Best answer Correct option (D) 1 :√3 : √2 (1 + 2 + 3)k = 180° ⇒ k = 30° Therefore, A = 30°, B = 60°, C = 90°. Now a:b:c = sin A:sin B:sin C 1/2 :√3/2:1 or 1: √3:√2 ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice Test
[Solved] In ΔABC, if a = 2, b = 4 and ∠C = 60° - Testbook
WebApr 12, 2024 · Q: Q1: Solve the complex equation: hint: cos z = 2.5 : ZEC cos(8₁ +8₂) = cos 0₁ cos 0₂ - sin 0₁ sin 0₂. A: I am going to solve the problem by using some simple trigonometry to get the required result of the… WebIn a right triangle ABC, right angled at B. If tanA=1 then verify that 2sinA.cosA=1 Medium View solution > If ABC is right angled at A, then cos(B+C) is Easy View solution > View more Get the Free Answr app Click a picture with our app and get instant verified solutions Scan Me OR Receive an SMS with download link +91 send optivia weight loss stories
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Web1. sin ( A − B) sin ( A + B) = sin A cos B − sin B cos A sin A cos B + sin B cos A = 2 a c cos B − 2 b c cos A 2 a c cos B + 2 b c cos A = ( a 2 − b 2 + c 2) − ( − a 2 + b 2 + c 2) ( a 2 − b 2 + c … WebIn Δ ABC, prove that a 3 sin(B – C) + b 3 sin(C – A) + c 3 sin(A – B) = 0. Advertisement Remove all ads. Solution Show Solution. By the sine rule, ... (sinC cosA - cosC sinA) + c 3 (sinA cosB - cosA sinB) `= a^3(b/kcos"C" - c/k cos"B") + b^3(c/kcos"A" - a/kcos"C") + c^3(a/kcos"B" - b/kcos"A")` Web工科数学分析第二版(下册)辅导及习题解析.pdf,工科数学分析第二版(下册)辅导及习题解析 第5章 向量代数与空间解析几何 5.1向量及其运算 内容提要 1.向・ (1)定义 既有大小又有方向的量称为向量. (2)向量的表示 用空间有向线段来表示向此记为*AB、 ….AB表示以A为起点,以8为 终点的向量.有向 ... optivia weight loss reviews+systems