Can memcpy given value as source address in c

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August undefined, 2024

WebJan 22, 2024 · Some (most) implementations of memcpy() assume that it can copy data in one specific direction which will cause data to be corrupted if areas overlap in the wrong way (e.g. if the implementation uses the "lowest address first" direction and the destination area overlaps and is at a higher address than the source, then writes to the destination ... WebNov 27, 2024 · No, you can't [portably] use memset for that purpose, unless the desired target value is 0.memset treats the target memory region as an array of bytes, not an array of ints.. A fairly popular hack for filling a memory region with a repetitive pattern is actually based on memcpy.It critically relies on the expectation that memcpy copies data in …

c++ - How to get float address for use with memcpy? - Stack Overflow

WebNov 20, 2014 · If you have allocated using malloc you must state the size of the array. int * src = malloc (ARRAY_LENGTH*sizeof (*src)); int * dst1 = malloc … WebMar 28, 2013 · As a basic type safety check it makes sure the sizes of source and destination elements are the same. That's evaluated at compilation time as well. … cute diy birthday gifts for friends

Byte copying in C (using memcpy?) - Stack Overflow

WebAug 12, 2015 · In Win32 API programming it's typical to use C struct s with multiple fields. Usually only a couple of them have meaningful values and all others have to be zeroed out. This can be achieved in either of the two ways: STRUCT theStruct; memset ( &theStruct, 0, sizeof ( STRUCT ) ); or. STRUCT theStruct = {}; WebJun 21, 2014 · The memcpy function copies n characters from the object pointed to by s2 into the object pointed to by s1. If copying takes place between objects that overlap, the … WebAug 3, 2015 · @PSkocik "Character type" is a term-of-art in the C standard which encompasses both single char objects and arrays of them (and probably some other stuff I don't remember off the top of my head). Regardless, the point is that char[4] and int are not compatible types and therefore you cannot use int* to access memory declared as … cheap art studio lighting

c - Using memcpy with hex values - Stack Overflow

c++ - Using `memcpy()` to assign a pointer an address

WebApr 29, 2004 · Optimizing Memcpy improves speed. Knowing a few details about your system-memory size, cache type, and bus width can pay big dividends in higher performance. The memcpy () routine in every C … WebMar 12, 2013 · you can use memcpy as, memcpy(&req_byte, (buf+4), 1); this will copy fifth byte of your message to req_byte. you can vary number after (+) in source buffer to … cheap art supplies bulkWebJan 7, 2016 · memcpy () is used to copy a block of memory from a location to another. It is declared in string.h // Copies "numBytes" bytes from address "from" to address "to" void * memcpy (void *to, const void *from, size_t numBytes); Below is a sample C program to … Before memset(): GeeksForGeeks is for programming geeks. After memset(): … cheap art schools in new york

"WebOct 2, 2024 · memcpy only copies from the beginning of an array if that's what address you pass it. The name of an array a is synonymous with the address of the first element &a [0], so if you do memcpy (dest, src, size), then the copy will be from the start of the array src. " - Can memcpy given value as source address in c

Can memcpy given value as source address in c

Byte copying in C (using memcpy?) - Stack Overflow

WebFeb 16, 2013 · As such, it has no address which could be given as parameter to memcpy or another function that expects a memory location. If you want to do this, you need to have a real constant (such as const int ), as suggested in the other answers. WebApr 8, 2024 · Also remember that argument in C are passed by value, meaning the value is copied into the argument variable. Modifying the argument variable (like assigning to it) …

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WebThe C library function void *memcpy (void *dest, const void *src, size_t n) copies n characters from memory area src to memory area dest. Declaration Following is the … WebJun 4, 2013 · I need a function that stores data into a void pointer. Here is a simple example of it: void saveData (void* data) { char inputData [] = "some data"; memcpy ( (char*)data, inputData, sizeof (inputData)); } However I get segmentation errors when I do this, even though it compiles just fine. My function argument has to be a void pointer because I ...

WebFeb 16, 2013 · Your constant (macro) is really just a literal. As such, it has no address which could be given as parameter to memcpy or another function that expects a …

WebOct 21, 2014 · But memcpy () is about copying memory objects, not values. An object resides at a given address, and contains a given value. Taking n gives the value, … WebNov 3, 2012 · First, memcpy () doesn't succeed or fail in the normal sense. It just copies the data, which might cause a fault/exception if it reads outside the source array or writes outside the destination array, and it might also read or write outside one of those arrays without causing any fault/exception and just silently corrupting data.

WebJul 11, 2013 · Understanding the source code of memcpy () 00018 void *memcpy (void *dst, const void *src, size_t len) 00019 { 00020 size_t i; 00021 00022 /* 00023 * memcpy …

WebMar 18, 2016 · C standard library often supports this technique, memcpy being another example. A possible use case might be something along the lines of char *clone_buffer (const char *buffer, size_t size) { return memcpy (new char [size], buffer, size); } If memcpy did not return the destination buffer pointer, we'd probably have to implement the above as cute diy christmas decorationsWebJan 21, 2016 · Define you own memcpy to copy to this address space : void my_memcpy( ptr8 addr_dest, const void * src, int len ) { memcpy( my_destination_memory + … cute diy birthday gifts for your momWebOct 25, 2015 · Save it to a .c file, like test.c, and compile it using gcc, like this: It will (most likely) behave differently. Try replacing memcpy with strncpy and see what happen. I hope the example is useful. With memcpy, the destination cannot overlap the source at all. With memmove it can. cheap art supplies online storeWebSo the answer is no; the check is not necessary (or yes; you can pass zero). Share Improve this answer Follow edited Sep 22, 2012 at 10:42 answered Sep 20, 2010 at 13:32 Mike Seymour 248k 28 442 637 1 Would a pointer be considered "valid" for purposes of such a function if it pointed to the location following the last element of an array? cute diy christmas room decorWebApr 17, 2012 · I am trying to read two integers, stored consecutively, from a memory block (i have a pointer void *block pointing to the contents of the block) using memcpy. The first one is read just fine using: memcpy (&test, block, sizeof (int)); I try to read the second using: memcpy (&test, block + sizeof (int), sizeof (int)); (Of course i am having ... cute diy christmas gifts for boyfriendWebOct 11, 2024 · When you refer to the address of a pointer, this normally means the pointer's own location in memory, not the value it holds (which also is an address). – Andreas Wenzel Oct 11, 2024 at 4:55 1 @N001: If you follow the advice I gave in my first comment, does your program then work as intended? Both printed pointer values are the same, then. cute diy christmas gifts for friendsWebOct 3, 2024 · 2 Answers. Sorted by: 5. It's how memcpy works: it takes a pointer to data it will copy. Your data is pointer to float, so you need to pass pointer to pointer to float: #include int main () { float f = 20.0f; float* pf = &f; char data [sizeof (pf)]; memcpy (data, &pf, sizeof (data)); } Share. cute diy bed rails for toddler girl